110, 41, 43, 95, 127, 99, 61, 92, 71, 93, 110, 36.
If 93 is replaced by 94, then consider the following statements:
1. The difference between new median and old median is 1.
2. The difference between new mean and old mean is less than 0·1.
3. The difference between new mode and old mode is zero.
Which of the statements given above are correct?
This question requires us to analyze how modifying a single data point affects the median, mean, and mode of a given data set. We need to calculate these measures for the original data and the modified data and then evaluate the given statements.
The original data set is:
110, 41, 43, 95, 127, 99, 61, 92, 71, 93, 110, 36.
First, let's sort the data in ascending order:
| 36 | 41 | 43 | 61 | 71 | 92 | 93 | 95 | 99 | 110 | 110 | 127 |
There are 12 data points (n=12). Since n is even, the median is the average of the 6th and 7th terms in the sorted list.
Old Median = \(\frac{92 + 93}{2} = \frac{185}{2} = 92.5\).
Sum of the original data = 110 + 41 + 43 + 95 + 127 + 99 + 61 + 92 + 71 + 93 + 110 + 36 = 978.
Old Mean = \(\frac{\text{Sum of data}}{\text{Number of data points}} = \frac{978}{12} = 81.5\).
The mode is the value that appears most frequently. In the original data set, the number 110 appears twice, while all other numbers appear only once.
Old Mode = 110.
The data point 93 is replaced by 94. The new data set is:
110, 41, 43, 95, 127, 99, 61, 92, 71, 94, 110, 36.
Let's sort the modified data:
| 36 | 41 | 43 | 61 | 71 | 92 | 94 | 95 | 99 | 110 | 110 | 127 |
The number of data points is still 12 (n=12). The new median is the average of the 6th and 7th terms.
New Median = \(\frac{92 + 94}{2} = \frac{186}{2} = 93\).
The sum changes by replacing 93 with 94. The change in sum is \(94 - 93 = 1\).
New Sum = Original Sum + 1 = 978 + 1 = 979.
New Mean = \(\frac{979}{12} \approx 81.5833\).
The difference between the new mean and the old mean is \(\frac{979}{12} - \frac{978}{12} = \frac{1}{12}\).
In the modified data set, the number 110 still appears twice, and all other numbers appear once.
New Mode = 110.
Difference = New Median - Old Median = \(93 - 92.5 = 0.5\).
Since \(0.5 \neq 1\), statement 1 is incorrect.
Difference = New Mean - Old Mean = \(\frac{1}{12}\).
As a decimal, \(\frac{1}{12} \approx 0.0833\).
Since \(0.0833 < 0.1\), statement 2 is correct.
Difference = New Mode - Old Mode = \(110 - 110 = 0\).
Statement 3 is correct.
Based on the analysis, statements 2 and 3 are correct.
Therefore, the correct option is the one that includes statements 2 and 3 only.
What is the median of the distribution ?
| Marks | Number of Candidates |
| More than 10 | 100 |
| More than 20 | 75 |
| More than 30 | 60 |
| More than 40 | 40 |
In a colony 5 families have 1 child, 7 families have 2 children, 8 families have 3 children and 3 families have 4 children.What is the mode of the number of children.
For which set of numbers do the mean, median and mode all have the same value?
The median of 5, 8, 25, 22, 34, 18 is
Find the mean of first 5 two-digit multiples of 4.
The difference between the upper limit and the lower limit of a class is called :