This question asks us to find the new arithmetic mean of a set of observations after applying a specific change: multiplying every observation by 5. We are given the original mean and the number of observations.
The arithmetic mean, often called the average, is calculated by summing up all the values in a dataset and then dividing by the count of those values. The formula is:
\(\bar{X} = \frac{\sum_{i=1}^{N} x_i}{N}\)
Where '\(\sum_{i=1}^{N} x_i\)' represents the sum of all observations (\(x_1, x_2, \dots, x_N\)) and \(N\) is the total number of observations.
First, let's use the given information to find the sum of the original observations.
We know that \(\bar{X} = 60\) and \(N = 200\). Plugging these into the formula:
\(60 = \frac{\sum_{i=1}^{200} x_i}{200}\)
To find the sum of the original observations, we multiply the mean by the number of observations:
\(\text{Sum of original observations} = \sum_{i=1}^{200} x_i = 60 \times 200 = 12000\)
Next, consider the effect of multiplying each observation by 5. Let the new observations be \(x'_i\). Then, \(x'_i = 5 \times x_i\) for each \(i\) from 1 to 200.
The sum of the new observations is:
\(\text{Sum of new observations} = \sum_{i=1}^{200} x'_i = \sum_{i=1}^{200} (5 x_i)\)
Using the properties of summation, we can pull the constant factor 5 out:
\(\sum_{i=1}^{200} (5 x_i) = 5 \times \sum_{i=1}^{200} x_i\)
We already calculated the sum of the original observations (\(12000\)), so:
\(\text{Sum of new observations} = 5 \times 12000 = 60000\)
Finally, to find the new arithmetic mean (\(\bar{X}_{new}\)), we divide the sum of the new observations by the number of observations (which is still 200):
\(\bar{X}_{new} = \frac{\text{Sum of new observations}}{N} = \frac{60000}{200}\)
\(\bar{X}_{new} = 300\)
There's a useful property of the arithmetic mean that simplifies this type of problem significantly. The property states:
If each observation in a dataset is multiplied by a constant value \(k\), the mean of the dataset is also multiplied by the same constant \(k\).
Mathematically, if \(x'_i = k \times x_i\), then the new mean \(\bar{X}_{new}\) is:
\(\bar{X}_{new} = k \times \bar{X}\)
Applying this property to our problem:
New Mean (\(\bar{X}_{new}\)):
\(\bar{X}_{new} = 5 \times 60\)
\(\bar{X}_{new} = 300\)
Both methods confirm that the new arithmetic mean is 300.
| Marks | Number of Candidates |
| More than 10 | 100 |
| More than 20 | 75 |
| More than 30 | 60 |
| More than 40 | 40 |
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