The Hall coefficient ($R_H$) is inversely proportional to the charge carrier density ($n$) and the charge of the carriers ($q$). For a metal with electrons as charge carriers (charge $-e$), the magnitude is:
$|R_H| = \frac{1}{ne}$The Sommerfeld model (free electron model) describes the Fermi energy ($E_F$) at absolute zero ($T=0K$) as a function of electron density ($n$):
$E_F = \frac{\hbar^2}{2m} (3\pi^2 n)^{2/3}$where $\hbar$ is the reduced Planck constant and $m$ is the electron mass.
To find the relationship between $R_H$ and $E_F$, we first express $n$ in terms of $E_F$ from the Fermi energy equation:
Now, substitute the expression for $n$ into the equation for $|R_H|$:
$|R_H| = \frac{1}{e \cdot n} = \frac{1}{e} \left[ \frac{3\pi^2}{\left(\frac{2mE_F}{\hbar^2}\right)^{3/2}} \right]$Simplify the expression:
$|R_H| = \left( \frac{3\pi^2 \hbar^6}{2e (2m)^{3/2}} \right) E_F^{-3/2}$The term in the parenthesis is a constant. Therefore, the Hall coefficient is proportional to $E_F$ raised to the power of $-3/2$.
$R_H \propto E_F^{-3/2}$Crystal structures of two metals A and B are two-dimensional square lattices with same lattice constant $a$. Electrons in metals behave as free electrons. The Fermi surfaces corresponding to A and B are shown by solid circles in figures. 
The electron concentrations in A and B are $n_A$ and $n_B$, respectively. The value of $(\frac{n_B}{n_A})$ is
If $X$ is the dimensionality of a free electron gas, the energy ($E$) dependence of density of states is given by $E^{½X-Y}$, where $Y$ is ________.