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Question

Complete the analogy: HJL : JLN :: QSU : ?

This question was previously asked in
SSC Stenographer 2025 Question Paper (06-Aug-2025) Shift 2
The correct answer is
SUW

Analogy Pattern Identification: HJL to JLN

The first part of the analogy compares 'HJL' to 'JLN'. We need to find the relationship between the letters in these two groups.

  • Comparing the first letter: H to J. The difference in their alphabetical positions is +2 (H $\rightarrow$ I $\rightarrow$ J).
  • Comparing the second letter: J to L. The difference in their alphabetical positions is +2 (J $\rightarrow$ K $\rightarrow$ L).
  • Comparing the third letter: L to N. The difference in their alphabetical positions is +2 (L $\rightarrow$ M $\rightarrow$ N).

The pattern identified is that each letter in the first group is shifted forward by 2 positions in the alphabet to get the corresponding letter in the second group.

Applying the Pattern: QSU to ?

Now, we apply the same +2 pattern to the second part of the analogy, 'QSU'.

  • First letter: Q. Applying the +2 shift: Q $\rightarrow$ R $\rightarrow$ S.
  • Second letter: S. Applying the +2 shift: S $\rightarrow$ T $\rightarrow$ U.
  • Third letter: U. Applying the +2 shift: U $\rightarrow$ V $\rightarrow$ W.

Following this pattern, 'QSU' becomes 'SUW'.

Conclusion

Therefore, the completed analogy is HJL : JLN :: QSU : SUW.

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