What is the output of the given C language code snippet? #include<stdio.h> void f(int n) { if(n==0) return; printf("%d ",n); f(n-1); } int main() { f(3); return 0; }
3 2 1
This question tests your understanding of recursion and the use of the `printf()` function in C language.
Let's analyze the code snippet step-by-step:
The recursive calls are completed, and the output generated is from the values of `n` that are printed in each recursive call.
Therefore, the output of the program is: 3 2 1
The correct answer is 3 2 1, which is obtained as described above.
The process of removing recursion involves replacing recursive function calls with:
#include <stdio.h>
int foo(int S[], int size){
if(size == 0) return 0;
if(size == 1) return 1;
if(S[0] != S[1]) return 1 + foo(S + 1, size - 1);
return foo(S + 1, size - 1);
}
int main(){
int A[] = {0, 1, 2, 2, 2, 0, 0, 1, 1};
printf("%d", foo(A, 9));
return 0;
}
The value printed by the given C program is _______ . (Answer in integer)
int bar(int n){
if (n == 1) return 0;
else return 1 + bar(n/2);
}
int foo(int n){
if (n == 1) return 1;
else return 1 + foo(bar(n));
}int func(int start, int end){
int length=end+1-start;
if((length < 1)||(start < 0)||(end < 0)){ return(0); }
if(length%3==0){
return(func(start+1, end));
} else if(length%3==1){
return(1+func(start, end-1));
} else {
return(func(start+2, end));
}
}