A. Gamma rays
B. Infrared rays
C. Visible rays
D. Ultraviolet rays
E. Radio waves
Choose the correct answer from the options given below :
The arrangement of electromagnetic waves is determined by their wavelength ($\lambda$), frequency ($f$), and energy ($E$). These properties are related: as wavelength increases, frequency and energy decrease. The order from shortest wavelength (highest frequency/energy) to longest wavelength (lowest frequency/energy) is key.
The main types of electromagnetic waves, ordered by increasing wavelength, are:
This order corresponds to decreasing frequency and energy.
Matching the given waves to their position in the spectrum by wavelength:
A. Gamma rays: Shortest wavelength
D. Ultraviolet rays: Shorter than visible
C. Visible rays: Middle range
B. Infrared rays: Longer than visible
E. Radio waves: Longest wavelength
Therefore, the correct arrangement in increasing order of wavelength is A, D, C, B, E.
Arrange the Hydrogen of the following compounds from most acidic to least acidic :
Choose the correct answer from the options given below :
| List - I (Number of d-electrons) | List - II (CFSE) |
|---|---|
| A. $\text{d}^{6}$ | I. $-0.4$ |
| B. $\text{d}^{4}$ | II. $-1.2$ |
| C. $\text{d}^{7}$ | III. $-0.8$ |
| D. $\text{d}^{8}$ | IV. $-0.6$ |
| List - I | List - II |
|---|---|
| A. Root mean square speed | I. $(8 \text{ kT}/\pi\mu)^{1/2}$ |
| B. Mean speed | II. $(8 \text{ RT}/\pi\text{M})^{1/2}$ |
| C. Most probable speed | III. $(3 \text{ RT}/\text{M})^{1/2}$ |
| D. Mean relative speed | IV. $(2 \text{ RT}/\text{M})^{1/2}$ |
| List-I | List-II |
| Electronic Configuration | First Ionisation energy (kJ mol$^{-1}$) |
| (A). ns$^2$ | (I). 2100 |
| (B). ns$^2$np$^1$ | (II). 1400 |
| (C). ns$^2$np$^3$ | (III). 800 |
| (D). ns$^2$np$^6$ | (IV). 900 |
| List-I | List-II |
| Spectroscopy | Property |
| (A). Raman | (I). Polarizability |
| (B). FTIR | (II). Dipole Moment |
| (C). UV-Visible | (III). Absorbance |
| (D). NMR | (IV). Spin |