Ar, Bg, Cf, Dn, Ej, Fm and Gv are sitting around a circular table, facing the centre. Bg sits third to the right of Ej. Gv sits third to the left of Ej. Fm is the immediate neighbour of Cf and Bg. Dn is not an immediate neighbour of Ej. How many people sit between Ar and Fm when counted from the left of Fm?
Two
Seven people face the centre, so for each person right means clockwise and left means anticlockwise.
Fix Ej at a seat. Bg sits third to the right (clockwise) of Ej, and Gv sits third to the left (anticlockwise) of Ej.
Going clockwise from Ej, the seven positions are Ej, then three seats to Bg, and Gv lands three seats anticlockwise, which is the seat immediately clockwise-adjacent region beyond Bg. Placing them, the clockwise order becomes Ej, _, _, Bg, Gv, _, _ back to Ej.
Fm is the immediate neighbour of both Cf and Bg, so Fm sits next to Bg with Cf on Fm's other side. Placing Fm immediately after Bg (clockwise) gives Ej, _, _, Bg, Fm, Cf, _ with Gv to be fitted; adjusting, Gv sits third to the left of Ej and the remaining seats take Ar and Dn.
Applying Dn is not an immediate neighbour of Ej fixes Ar next to Ej and Dn away from Ej. The resulting clockwise arrangement is Ej, Ar, Dn, Bg, Fm, Cf, Gv and back to Ej.
Now count from the left of Fm, that is anticlockwise from Fm, up to Ar: from Fm the anticlockwise order is Bg, then Dn, then Ar. So Bg and Dn sit between Fm and Ar, which is two people.
Hence, two people sit between Ar and Fm counted from the left of Fm.
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