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Question

An object of mass 2000 g possesses 100 J kinetic energy. The object must be moving with a speed of

The correct answer is

10.0 m/s

Calculating Object Speed from Kinetic Energy and Mass

This problem asks us to find the speed of an object given its mass and kinetic energy. Kinetic energy is the energy an object possesses due to its motion. The formula relating kinetic energy, mass, and speed is a fundamental concept in physics.

Understanding Kinetic Energy

Kinetic energy ($\text{KE}$) is directly proportional to the mass ($m$) of the object and the square of its velocity or speed ($v$). The standard formula is:

$\text{KE} = \frac{1}{2}mv^2$

In this problem, we are given the kinetic energy and the mass, and we need to find the speed ($v$). We will rearrange the formula to solve for $v$.

Given Information

  • Mass ($m$) = 2000 g
  • Kinetic Energy ($\text{KE}$) = 100 J

Units Conversion

The standard units for mass in physics calculations like kinetic energy are kilograms (kg), and for kinetic energy, it's Joules (J). Speed is typically in meters per second (m/s). We need to convert the mass from grams to kilograms.

1 kilogram (kg) = 1000 grams (g)

So, the mass in kilograms is:

$m = 2000 \text{ g} \times \frac{1 \text{ kg}}{1000 \text{ g}}$

$m = 2 \text{ kg}$

Rearranging the Kinetic Energy Formula for Speed

We start with the kinetic energy formula:

$\text{KE} = \frac{1}{2}mv^2$

Multiply both sides by 2:

$2 \cdot \text{KE} = mv^2$

Divide both sides by $m$:

$\frac{2 \cdot \text{KE}}{m} = v^2$

Take the square root of both sides to solve for $v$:

$v = \sqrt{\frac{2 \cdot \text{KE}}{m}}$

Calculating the Speed

Now, substitute the given values (with the mass in kg) into the rearranged formula:

$v = \sqrt{\frac{2 \cdot 100 \text{ J}}{2 \text{ kg}}}$

$v = \sqrt{\frac{200 \text{ J}}{2 \text{ kg}}}$

$v = \sqrt{100 \text{ J/kg}}$

Recall that 1 Joule (J) is equal to 1 kg⋅m²/s². So, J/kg is equivalent to (kg⋅m²/s²)/kg = m²/s².

$v = \sqrt{100 \text{ m}^2/\text{s}^2}$

$v = 10 \text{ m/s}$

Summary of Calculation Steps

Step Description Value/Formula
1 Convert mass to kg $m = 2000 \text{ g} = 2 \text{ kg}$
2 Kinetic Energy Formula $\text{KE} = \frac{1}{2}mv^2$
3 Rearrange for $v$ $v = \sqrt{\frac{2 \cdot \text{KE}}{m}}$
4 Substitute values $v = \sqrt{\frac{2 \cdot 100 \text{ J}}{2 \text{ kg}}}$
5 Calculate $v = \sqrt{100 \text{ m}^2/\text{s}^2} = 10 \text{ m/s}$

The calculated speed of the object is 10.0 m/s.

Revision Table: Kinetic Energy and Speed

Concept Definition Formula Units (SI)
Kinetic Energy ($\text{KE}$) Energy of motion $\text{KE} = \frac{1}{2}mv^2$ Joules (J)
Mass ($m$) Amount of matter in an object - Kilograms (kg)
Speed ($v$) Magnitude of velocity $v = \sqrt{\frac{2 \cdot \text{KE}}{m}}$ Meters per second (m/s)

Additional Information on Energy Concepts

  • Kinetic energy is a scalar quantity, meaning it only has magnitude and no direction.
  • The unit of energy, the Joule (J), is defined as the work done when a force of one Newton (N) acts over a distance of one meter (m). $1 \text{ J} = 1 \text{ N} \cdot \text{m}$.
  • From Newton's second law ($F=ma$), $1 \text{ N} = 1 \text{ kg} \cdot \text{m/s}^2$.
  • Therefore, $1 \text{ J} = (1 \text{ kg} \cdot \text{m/s}^2) \cdot 1 \text{ m} = 1 \text{ kg} \cdot \text{m}^2/\text{s}^2$. This confirms the unit analysis done during the calculation.
  • The relationship between kinetic energy and speed is squared, meaning if you double the speed, the kinetic energy increases by a factor of four.
  • Other forms of energy include potential energy (gravitational, elastic), thermal energy, chemical energy, etc.
  • The principle of conservation of energy states that energy cannot be created or destroyed, only transformed from one form to another in an isolated system.
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Important Questions from Kinetic Energy

  1. A swimmer can achieve a speed of $4$ km/h in still water. If the river current flows at $2$ km/h, and the swimmer aims to cross the river landing directly opposite their starting point, what is the magnitude of the swimmer's effective velocity perpendicular to the river flow?
  2. The kinetic energy of the particles of ______ is maximum.

  3. An object of mass 10 kg is moving with a uniform velocity of 2 m/s. What will be the kinetic energy of the object?

  4. A speeding bullet or a running person are examples of system having ________ energy.

  5. A mass of 5 kg is moving along a circular path of radius 1 m. If the mass moves with 300 revolutions per minute, its kinetic energy would be:

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