$HCo(CO)_4$
Hydroformylation, also known as the oxo process, involves adding a hydrogen atom and a formyl group (-CHO) across an olefin's double bond, typically producing aldehydes.
The catalyst mentioned is $Co_2(CO)_8$ (dicobalt octacarbonyl). In the presence of hydrogen (H$_2$) and carbon monoxide (CO) under pressure, this precatalyst activates to form the actual catalytic species.
The primary pathway for activating $Co_2(CO)_8$ involves reaction with hydrogen gas to form the hydrido cobalt carbonyl complex. This is often represented by the equilibrium:
$ Co_2(CO)_8 + H_2 \rightleftharpoons 2 HCo(CO)_4 $
This equation shows the formation of $HCo(CO)_4$ (tetracarbonylhydridocobalt).
Therefore, the intermediate formed from $Co_2(CO)_8$ during hydroformylation is $HCo(CO)_4$.
The reaction that proceeds through an oxidative addition followed by a reductive elimination is
[Given: Atomic numbers Ni = 28, Ta = 73, Zr = 40, Pt = 78]
The heptacity of allyl and Cp and the ligation mode of NO in the thermodynamically stable complexes
$[(\eta^x-allyl)Ru(CO)_2(NO)]$ and $[(\eta^y-Cp)Ru(CO)_2(NO)]$,
respectively, are
(The heptacity of allyl and Cp are denoted by $\eta^x$ and $\eta^y$, respectively.)
The hapticity of cycloheptatriene, $(C_7H_8)$, in $Mo(C_7H_8)(CO)_3$ is ______________.
The bond angle (Ti-C-C) in the crystal structure of
is severely distorted due to
The major product of the following reaction sequence is
