Alloy A contains copper and zinc in the ratio of 4 ∶ 3 and alloy B contains copper and zinc in the ratio 5 ∶ 2. A and B are taken in the ratio of 5 ∶ 6 and melted to form a new alloy. The percentage of zinc in the new alloy is closest to∶
35
Zinc fraction in A is \(\tfrac{3}{7}\); in B it is \(\tfrac{2}{7}\). Taking 5 units of A and 6 units of B (total 11 units):
Zinc from A: \(5\times\tfrac{3}{7}=\tfrac{15}{7}\)
Zinc from B: \(6\times\tfrac{2}{7}=\tfrac{12}{7}\)
Total zinc: \(\tfrac{15}{7}+\tfrac{12}{7}=\tfrac{27}{7}\) in 11 units.
\[\text{Zinc \%}=\frac{27/7}{11}\times100=\frac{2700}{77}\approx 35.06\%\]
Closest option is 35.
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