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Question

Acar moving along a straight path slows down and stops. The car is under which type of motion?

This question was previously asked in
RRB NTPC 2024 Undergraduate CBT 1 Question Paper (29-Aug-2025) (Shift 1)
The correct answer is

Non-uniform motion

Understanding Car Motion: Straight Path, Slowing Down

The question describes a car moving on a straight path and then slowing down until it stops. We need to identify the type of motion this represents.

Analysing Motion Types

Let's examine the definitions of the different types of motion mentioned in the options:

  • Periodic Motion: This is motion that repeats itself at regular time intervals. Examples include a pendulum swinging or the Earth revolving around the Sun. A car slowing down and stopping doesn't fit this pattern.
  • Circular Motion: This is motion along a circular path. The question explicitly states the car is moving along a straight path, so this option is incorrect.
  • Uniform Motion: This is motion where an object travels at a constant velocity. This means both its speed and direction remain unchanged. For example, a car travelling at exactly 60 km/h in a straight line without any change.
  • Non-uniform Motion: This is motion where an object's velocity changes over time. The velocity can change in magnitude (speed) or direction, or both.

Why Non-uniform Motion Applies

The key information in the question is that the car is slowing down and eventually stops.

  • Slowing down means the car's speed is decreasing.
  • Stopping means the car's final speed is zero.

Since the car's speed is changing (decreasing from some initial speed to zero), its velocity is not constant.

According to the definition, motion with a changing velocity is called non-uniform motion. Even though the car moves along a straight path (constant direction), the change in speed is sufficient to classify the motion as non-uniform.

In physics terms, a change in velocity indicates the presence of acceleration (\(a\)). Here, the acceleration is negative (or deceleration) because the speed is decreasing: \(a = \frac{\Delta v}{\Delta t}\). Since \(v\) is changing, \(a\) is non-zero, confirming non-uniform motion.

Conclusion

Because the car's speed is changing as it slows down and stops on a straight path, it is undergoing non-uniform motion.

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Similar Questions

  1. What is the path of an object when it is in uniform motion?

  2. Why do cars have treaded tyres?

  3. Neha swims in a pool that is 50 metres long. She covers 100 metres in 1 minute by swimming from one end of the pool to the other and back along the same straight path. Find her average velocity (in m/s).
  4. A force acts on a 4 kg body at rest and produces an acceleration of 3 m/s². The final velocity after 5 seconds is:
  5. A car falls off a ledge and drops to the ground in 0.8 s. Take g = 10 m/s² (for simplifying the calculations). How high is the ledge from the ground?
  6. The area under the velocity-time curve between times t1 and t2 is equal to the _____ of the object during that interval of time.
  7. Pihu starts her car at 9 a.m. to reach her office, which is 20 km away. She covers the first 10 km in 30 minutes and reaches her office at 10 a.m. Pihu's motion is _______.

  8. Which of the following is an example of uniform motion?

  9. Which of the following physical quantities represents the rate of change of velocity?

  10. Which of the following physical quantities is equivalent to the total path length covered by a moving body?


Important Questions from Motion

  1. An object is covering distance in direct proportion to the square of time elapsed. What conclusion can be drawn about the motion of the object?

  2. If the distance time graph of the motion of an object is a straight line but not parallel to the time axis, then it may be concluded that the object is moving with a:

  3. Which of the following changes when a body performs uniform circular motion?

  4. Vehicles have treaded tires so that it_______.

  5. If the initial velocity of an object thrown upwards is 14 m/s, then the time taken for the object to reach its highest point will be_______. (a = 9.8 m/s2)

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