ABCD is a quadrilateral in which AB || DC, and E and F are the mid points of the diagonals AC and BD, respectively. If AB = 24 cm, BC = 62 cm, DC = 92 cm, and AD = 95 cm, then what is the length (in cm) of EF?
34
In a trapezium with AB parallel to DC, the segment joining the midpoints of the diagonals is parallel to the two parallel sides.
The length of this segment equals half the positive difference of the lengths of the parallel sides, that is, \(EF = \frac{|DC - AB|}{2}\).
Substituting the given values, \(EF = \frac{|92 - 24|}{2} = \frac{68}{2} = 34\) cm.
Hence, the length of EF is 34 cm.
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Important Questions from Quadrilaterals
What is the value of AC 2– BD 2
What is the point of intersection of the diagonals?
What is the area of the parallelogram?
ABCD is a cyclic quadrilateral. Diagonals BD and AC intersect each other at E. If ∠BEC = 138° and ∠ECD = 35°, then what is the measure of ∠BAC?
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