The sum of the interior angles of any quadrilateral is always 360 degrees. We are given that the angles are in the ratio 2 : 4 : 6 : 8.
We set up an equation using the sum of the angles:
$2x + 4x + 6x + 8x = 360^\circ$
Combine the terms:
$20x = 360^\circ$
Solve for $x$:
$x = \frac{360^\circ}{20}$
$x = 18^\circ$
Now, we find the measure of each angle:
The smallest angle corresponds to the smallest part of the ratio, which is $2x$. Therefore, the smallest angle is $36^\circ$.
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ABCD is a cyclic quadrilateral. Diagonals BD and AC intersect each other at E. If ∠BEC = 138° and ∠ECD = 35°, then what is the measure of ∠BAC?
A circle is inscribed in a quadrilateral ABCD, touching sides AB, BC CD and DA at P, Q, R and S, respectively. If AS = 6 cm, BC = 12 cm, and CR = 5 cm, then the length of AB (in cm) is: