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Question

The diagonals of a quadrilateral ABCD bisect each other. In this quadrilateral, if $\angle A = 45^{\circ}$ then $\angle B =$ ?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$135^{\circ}$

The problem states that the diagonals of a quadrilateral ABCD bisect each other. This is a key property that defines a parallelogram.

Parallelogram Property Identification

A quadrilateral whose diagonals bisect each other is always a parallelogram. Therefore, ABCD is a parallelogram.

Adjacent Angles in a Parallelogram

In any parallelogram, consecutive (adjacent) angles are supplementary. This means their sum is equal to $180^{\circ}$.

So, for parallelogram ABCD:

  • $\angle A + \angle B = 180^{\circ}$
  • $\angle B + \angle C = 180^{\circ}$
  • $\angle C + \angle D = 180^{\circ}$
  • $\angle D + \angle A = 180^{\circ}$

Calculating Angle B

We are given that $\angle A = 45^{\circ}$. Using the property that adjacent angles are supplementary:

$ \angle A + \angle B = 180^{\circ} $

Substitute the value of $\angle A$:

$ 45^{\circ} + \angle B = 180^{\circ} $

To find $\angle B$, subtract $45^{\circ}$ from both sides:

$ \angle B = 180^{\circ} - 45^{\circ} $

$ \angle B = 135^{\circ} $

Therefore, the measure of angle B is $135^{\circ}$.

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Important Questions from Quadrilaterals

  1. What is the value of AC 2– BD 2

  2. What is the point of intersection of the diagonals?

  3. What is the area of the parallelogram?

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