We are analyzing a right-angled triangle named ABC, where angle C is the right angle (90°).
In a right-angled triangle, the cosine function relates the angle, the adjacent side, and the hypotenuse:
$cos(Angle) = Adjacent / Hypotenuse$
Applying this to Angle A:
$\cos(A) = \frac{AC}{AB}$
Substitute the known values into the formula:
$\cos(60^\circ) = \frac{20\sqrt{3}}{AB}$
Recall the value of $\cos(60^\circ)$, which is $\frac{1}{2}$.
So, the equation becomes:
$\frac{1}{2} = \frac{20\sqrt{3}}{AB}$
Rearrange the equation to solve for AB:
$AB = 2 \times 20\sqrt{3}$
$AB = 40\sqrt{3}$
The length of the hypotenuse AB is $40\sqrt{3}$ units.
The given equation can be reduced to
If sin2x = a - b√c, where a and b are natural numbers and c is prime number, then what is the value of a - b + 2c ?
Let θ be a positive angle. If the number of degrees in θ is divided by the number of radians in θ, then an irrational number 180 / π results. If the number of degrees in θ is multiplied by the number of radians in θ, then an irrational number 125π / 9 results. The angle θ must be equal to
What is sin 2α equal to?
If \(\sin θ = \frac{8}{{17}}\) , then find the value of tan θ.