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Question

A wire carrying current is placed between the poles of a magnet. It experiences maximum force when it _____.

The correct answer is
is perpendicular to the magnetic field

Magnetic Field Force Maximum Condition

The force experienced by a current-carrying wire of length L placed in a magnetic field B carrying current I is given by the formula:

$ F = I L B \sin \theta $

Here, F is the magnitude of the force, I is the current in the wire, L is the length of the wire segment within the magnetic field, B is the magnitude of the magnetic field, and θ is the angle between the direction of the current (wire) and the direction of the magnetic field.

Condition for Maximum Force

To find when the force F is maximum, we need to maximize the term \sin θ in the equation.

  • The maximum value of the sine function, sin θ, is 1.
  • This maximum value occurs when the angle θ is 90 degrees (or $ \frac{\pi}{2} $ radians).

When $ \sin \theta = 1 $, the force equation becomes:

$ F_{max} = I L B $

An angle of θ = 90° means that the wire carrying the current is perpendicular to the magnetic field lines.

Conclusion

Therefore, the wire experiences maximum force when it is perpendicular to the magnetic field.

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Important Questions from Magnetic Force on a Current-Carrying Wire

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