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Question

A triangular prism has a base with area 45 $\text{cm}^2$ and height 14 cm. If 10% of the prism is hollowed out for wiring, what is the volume of the solid part?

This question was previously asked in
SSC CGL 2025 Tier 1 Question Paper (25-Sep-2025) (Shift 3)
The correct answer is
$567\text{ cm}^3$

Triangular Prism Solid Volume Calculation

The volume of any prism is found by multiplying its base area by its height.

The formula is:

$ V = \text{Base Area} \times \text{Height} $

Total Prism Volume Calculation

We are given the following information:

  • Base Area = \(45 \text{ cm}^2\)
  • Height = \(14 \text{ cm}\)

First, calculate the total volume of the prism:

$ V_{\text{total}} = 45 \text{ cm}^2 \times 14 \text{ cm} $

$ V_{\text{total}} = 630 \text{ cm}^3 $

Solid Part Volume Calculation

10% of the prism's volume is hollowed out for wiring. This means the remaining solid part represents 90% of the total volume.

Percentage of solid part = \(100\% - 10\% = 90\%\)

Now, calculate the volume of the solid part:

$ V_{\text{solid}} = 90\% \times V_{\text{total}} $

$ V_{\text{solid}} = 0.90 \times 630 \text{ cm}^3 $

$ V_{\text{solid}} = 567 \text{ cm}^3 $

Therefore, the volume of the solid part of the triangular prism is \(567 \text{ cm}^3\).

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Important Questions from Mensuration

  1. The areas of three adjacent faces of a cuboidal tank are 3 m 2, 12 m 2 and 16 m 2. the capacity of the tank, in litres, is:

  2. Volume of a cuboid is 4800 cm 3. If the height of this cuboid is 20 cm, then what will be the area of the base of cuboid ?

  3. Two similar cubes have heights of 8 cm and 12 cm, respectively. If the capacity of the smaller cube is 80 cm 3, what is the capacity of the bigger cube (in cm 3)?

  4. Three circles of radius 7 cm are kept touching each other. The string is tightly tied around these three circles. What is the length of the string?

  5. Three circles of radius 6 cm are kept touching each other. The string is tightly tied around these three circles. What is the length of the string?

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