The volume of any prism is found by multiplying its base area by its height.
The formula is:
$ V = \text{Base Area} \times \text{Height} $
We are given the following information:
First, calculate the total volume of the prism:
$ V_{\text{total}} = 45 \text{ cm}^2 \times 14 \text{ cm} $
$ V_{\text{total}} = 630 \text{ cm}^3 $
10% of the prism's volume is hollowed out for wiring. This means the remaining solid part represents 90% of the total volume.
Percentage of solid part = \(100\% - 10\% = 90\%\)
Now, calculate the volume of the solid part:
$ V_{\text{solid}} = 90\% \times V_{\text{total}} $
$ V_{\text{solid}} = 0.90 \times 630 \text{ cm}^3 $
$ V_{\text{solid}} = 567 \text{ cm}^3 $
Therefore, the volume of the solid part of the triangular prism is \(567 \text{ cm}^3\).
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