The problem describes a scenario that can be modeled using a right-angled triangle.
Given values:
We use the Pythagorean theorem to find the length of the broken part (hypotenuse, c):
$ a^2 + b^2 = c^2 $
Substitute the given values:
$ 8^2 + 6^2 = c^2 $
$ 64 + 36 = c^2 $
$ 100 = c^2 $
Solve for c:
$ c = \sqrt{100} $
$ c = 10 \text{ m} $
So, the length of the broken upper part is 10 m.
The total height of the tree is the sum of the standing part and the broken part.
Total Height = Standing Part (a) + Broken Part (c)
Total Height = 8 m + 10 m
Total Height = 18 m
The height of the tree is 18 m.
Two ships are sailing in the sea on the two sides of a lighthouse. The angles of elevation of the top of the lighthouse as observed from the ships are 45 ° and 60° respectively. If the lighthouse is 81 m high, then the distance between two ships is:
The horizontal distance between two towers is 40√3 m. The angle of depression of the top of the first tower when seen from the top of the second tower is 30°. If the height of the second tower is 130 m, find the height of the first tower.
The angle of elevation of a ladder leaning against a house is 60° and the foot of the ladder is 6.5 metres from the house. The length of the ladder is
A kite is flying at a height of 50 m. If the length of the string is 100 m then the inclination of the string to the horizontal ground in degree measures is:
A. 90
B. 45
C. 60
D. 30
Two poles of the height 15 m and 20 m stand vertically upright on a plane ground. If the distance between their feet is 12 m, find the distance between their tops.
A. 11 m
B. 12 m
C. 13 m
D. 14 m