A transformer has 350 primary turns and 1050 secondary turns. The primary winding is connected across a 230 V, 50 Hz supply. The induced EMF in the secondary will be
690 V, 50 Hz
A transformer is an electrical device that transfers electrical energy between two or more circuits through electromagnetic induction. It is commonly used to increase or decrease AC voltages. The relationship between the voltages and the number of turns in the primary and secondary windings of an ideal transformer is crucial for understanding its operation.
The core principle governing a transformer's operation is the transformer turns ratio. This ratio relates the primary voltage to the secondary voltage based on the number of turns in each winding. Additionally, a key characteristic of transformers is that they do not change the frequency of the AC supply.
Let's list the given parameters for this transformer question:
To find the induced EMF (voltage) in the secondary winding, we use the transformer turns ratio formula:
\[\frac{V_s}{V_p} = \frac{N_s}{N_p}\]
Where:
Rearranging the formula to solve for \(V_s\):
\[V_s = V_p \times \frac{N_s}{N_p}\]
Now, let's substitute the given values into the formula:
\[V_s = 230 \, \text{V} \times \frac{1050 \, \text{turns}}{350 \, \text{turns}}\]
First, simplify the turns ratio:
\[\frac{1050}{350} = 3\]
Now, multiply this ratio by the primary voltage:
\[V_s = 230 \, \text{V} \times 3\]
\[V_s = 690 \, \text{V}\]
So, the induced EMF in the secondary winding is 690 V.
A fundamental characteristic of an ideal transformer is that it does not alter the frequency of the AC voltage and current. The frequency of the induced EMF in the secondary winding will always be the same as the frequency of the AC supply connected to the primary winding.
Given the primary frequency (\(f_p\)) is 50 Hz, the secondary frequency (\(f_s\)) will also be:
\[f_s = f_p = 50 \, \text{Hz}\]
Combining both the calculated secondary voltage and frequency, the induced EMF in the secondary will be 690 V, 50 Hz.
Two inductors whose self-inductance is 80 mH and 60 mH are connected in parallel aiding. The equivalent inductance of the combination is 48.75 mH. Calculate their mutual inductance.
Two inductors L1 = 20 mH and L2 = 40 mH are connected in series so that their equivalent inductance is 50 mH. The mutual inductance between the two coils is _______.
Which of the following devices does not work on the principle of mutual induction?
Which statement is INCORRECT for mutual inductance?
Calculate the total inductance (in H) of the circuit shown below: