Solving Train Travel Time with Increased Speed
The question asks to find the time taken by a train to cover a distance of $360 \text{ km}$ after its speed is increased by $10 \text{ km/h}$. We first need to determine the initial speed of the train.
Initial Speed Calculation
- Given: Distance = $360 \text{ km}$, Initial Time = $4 \text{ hours}$.
- Formula: Speed = $\frac{\text{Distance}}{\text{Time}}$
- Calculation: Initial Speed ($s_1$) = $\frac{360 \text{ km}}{4 \text{ h}} = 90 \text{ km/h}$.
New Speed and Time Calculation
- New Speed: The speed is increased by $10 \text{ km/h}$.
- New Speed ($s_2$) = Initial Speed + $10 \text{ km/h}$ = $90 \text{ km/h} + 10 \text{ km/h} = 100 \text{ km/h}$.
- Distance: The distance remains the same, $360 \text{ km}$.
- Formula: Time = $\frac{\text{Distance}}{\text{Speed}}$
- Calculation: New Time ($t_2$) = $\frac{360 \text{ km}}{100 \text{ km/h}} = 3.6 \text{ hours}$.
Therefore, the train will take $3.6 \text{ hours}$ to cover the same distance with the increased speed.
Similar Questions
- A train 120 meters long takes 6 seconds to cross a man. What is the speed of the train in km/h?
Important Questions from Problem on Trains
A train is to cover 370 km at a uniform speed. After running 100 km, the train could run at a speed 5 km/h less than its normal speed due to some technical fault. The train got delayed by 36 minutes. What is the normal speed of the train, in km/h?
A train travelling at 36 km/h crosses a pole in 25 seconds. How much time (in seconds) will it take to cross a bridge 250 m long?
A train covers 450 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less to cover the same distance. How much time will it take to cover 315 km at its usual speed?
A train crosses a pole in 12 sec, and a bridge of length 170 m in 36 sec. Then the speed of the train is:
The ratio of the speeds of two trains is 2 : 7. If the first train runs 250 km in 5 hours, then the sum of the speeds (in km/h) of both the trains is:
