Calculating Train Speed in km/h
The question asks for the speed of a train in kilometers per hour (km/h). We are given the train's length and the time it takes to cross a stationary man.
Key Information Provided
- Train Length: 120 meters
- Time to Cross Man: 6 seconds
Speed Calculation Steps
To find the speed of the train, we use the formula: Speed = Distance / Time.
- Determine the Distance: When a train crosses a man (or a pole), the distance the train covers is equal to its own length.
Distance = 120 meters
- Calculate Speed in m/s: Use the given time to find the speed in meters per second.
Speed (m/s) = \(\frac{\text{Distance}}{\text{Time}}\) = \(\frac{120 \text{ m}}{6 \text{ s}}\) = 20 m/s
- Convert Speed to km/h: To convert meters per second (m/s) to kilometers per hour (km/h), multiply by the conversion factor \(\frac{18}{5}\).
Speed (km/h) = Speed (m/s) \(\times\) \(\frac{18}{5}\)
Speed (km/h) = 20 \(\times\) \(\frac{18}{5}\)
Speed (km/h) = 4 \(\times\) 18
Speed (km/h) = 72 km/h
The speed of the train is 72 km/h.
Similar Questions
- A train travels a distance of $360 \text{ km}$ in $4 \text{ hours}$. If the train increases its speed by $10 \text{ km/h}$, how much time will it take to cover the same distance?
Important Questions from Problem on Trains
A train is to cover 370 km at a uniform speed. After running 100 km, the train could run at a speed 5 km/h less than its normal speed due to some technical fault. The train got delayed by 36 minutes. What is the normal speed of the train, in km/h?
A train travelling at 36 km/h crosses a pole in 25 seconds. How much time (in seconds) will it take to cross a bridge 250 m long?
A train covers 450 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less to cover the same distance. How much time will it take to cover 315 km at its usual speed?
A train crosses a pole in 12 sec, and a bridge of length 170 m in 36 sec. Then the speed of the train is:
The ratio of the speeds of two trains is 2 : 7. If the first train runs 250 km in 5 hours, then the sum of the speeds (in km/h) of both the trains is:
