A train leaves Station A at 6:00 AM and travels towards Station B at a constant speed of 60 km/h. Another train leaves Station B at 8:00 AM and travels towards Station A at a constant speed of 90 km/h. The distance between the two stations is 540 km. At what time will the two trains meet?
10:48 AM
Step 1 – Distance covered by Train 1 before Train 2 starts (6:00 AM to 8:00 AM, 2 hours):
\(60 \times 2 = 120 \text{ km}\)
Step 2 – Remaining distance between the two trains at 8:00 AM:
\(540 - 120 = 420 \text{ km}\)
Step 3 – Trains move towards each other; relative speed:
\(60 + 90 = 150 \text{ km/h}\)
Step 4 – Time to meet from 8:00 AM:
\(\dfrac{420}{150} = 2.8 \text{ hours} = 2 \text{ h } 48 \text{ min}\)
Step 5 – Meeting time:
\(8\!:\!00 \text{ AM} + 2\text{h } 48\text{ min} = 10\!:\!48 \text{ AM}\)
Hence the two trains meet at 10:48 AM.
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