A theater lighting designer must ensure that each part of the stage receives the same amount of illumination from overhead lights. If the distance between the lights and the stage is doubled, which action will maintain equal illumination across all areas, according to the laws of illumination?
Increase the luminous intensity of each light source by a factor of four
To determine how to maintain equal illumination across all areas of the stage when the distance between the lights and the stage is doubled, we need to understand the inverse square law of illumination.
Concept Explanation:
The illumination (\(E\)) on a surface from a point light source is inversely proportional to the square of the distance (\(d\)) from the light source. Mathematically, this is expressed as:
\(E \propto \frac{I}{d^2}\)
Where \(I\) is the luminous intensity of the light source.
If the distance is doubled, the new distance (\(d'\)) becomes \(2d\). Thus, the new illumination \(E'\) becomes:
\(E' = \frac{I}{(2d)^2} = \frac{I}{4d^2}\)
This shows that the illumination is reduced to a quarter of its original value (\(\frac{1}{4}\) of \(E\)) if the distance is doubled.
Solution:
To maintain the same level of illumination, we need to compensate for the reduced illumination by increasing the luminous intensity. From the relationship above, to restore \(E\) to its original level when \(E'\) is \(\frac{1}{4}\) of \(E\), the luminous intensity needs to be quadrupled:
\(I' = 4I\)
This means we must increase the luminous intensity of each light source by a factor of four to maintain equal illumination.
Conclusion:
The correct action, according to the laws of illumination, is to increase the luminous intensity of each light source by a factor of four. This is why the correct answer is Option B.
Other options are incorrect because:
How many 200 linear lamps are required to obtain a minimum illuminance of 50 lux in a 5 m and 8 m rectangular hall?
Intensity of light is measured in:
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