A sum of money amounts to ₹19,360 in 3 years at 10% per annum, compounded annually. The compound interest (in ₹) earned is (Round off your answer to the nearest paise.)
₹4814.55
The amount after compound interest is given by \(A = P\left(1 + \frac{R}{100}\right)^n\).
Here \(A = 19360\), \(R = 10\%\) and \(n = 3\).
The growth factor is \(\left(1 + \frac{10}{100}\right)^3 = (1.1)^3 = 1.331\).
So the principal \(P = \frac{19360}{1.331} = 14545.4545...\)
Compound interest \(= A - P = 19360 - 14545.4545 = 4814.5455\), which rounds to ₹4814.55.
Hence, the compound interest earned is ₹4814.55.
Find the total amount (in ₹) on ₹4500 at 12% per annum for 2 years and 8 months compounded annually.
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In how many years will a sum of Rs.1875 amount to Rs.2187 at 8 percent p.a. compound interest?
A sum of money has increased by 45% in 9 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate?
At a certain rate of compound interest a certain sum amounts to Rs. 64800 in 4 years and Rs. 93312 in 6 years. What is the compound interest earned in fifth year?