A student studies 1.75 hours morning and 2.25 hours evening for 5 days, rests 1 day. Find average over 6 days.
3.33
Each study day, for 5 days, totals the morning and evening hours combined.
\(1.75 + 2.25 = 4\) hours per study day.
Total hours studied over 6 days, with the 6th day being a rest day of 0 hours: \(5 \times 4 + 0 = 20\) hours.
The average over 6 days is found by dividing the total hours by 6: \(\frac{20}{6} = 3.33\)
Hence, the average is 3.33 hours.
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