A student's marks were entered incorrectly as 84 instead of the correct value of 100. This difference affects the overall class average.
Calculate the difference:
Difference = Correct Marks - Incorrect Marks
Difference = \(100 - 84 = 16\)
This means the total sum of marks for the class is lower by 16 due to the error.
The problem states that the class average decreased by \(\frac{8}{7}\) because of this incorrect entry.
Let \(N\) be the total number of students in the class.
The decrease in the average is directly related to the difference in total marks and the number of students:
Average Decrease = \(\frac{\text{Total Marks Difference}}{N}\)
Substitute the known values:
\(\frac{8}{7} = \frac{16}{N}\)
Solve the equation \(\frac{8}{7} = \frac{16}{N}\) for \(N\) to find the number of students.
Cross-multiply:
\(8 \times N = 16 \times 7\)
\(8N = 112\)
Divide both sides by 8:
\(N = \frac{112}{8}\)
\(N = 14\)
Therefore, there are 14 students in the class.
| Marks obtained | No. of students |
| 25 | 5 |
| 30 | 6 |
| 35 | 3 |
| 40 | 1 |
| Age Band | Students |
|---|---|
| 0 - 10 | 4 |
| 10 - 20 | 5 |
| 20 - 30 | 15 |
| 30 - 40 | 4 |
The median of the observations 4, 14, 11, 8, 7, 8, 9, 12, 4, and 6 is:
The weights (in kg) of 9 members of a school cricket team are 50, 63, x, 62, 64, 48, 51, 55, 48. If the mean weight is 56 kg, then the value of x is:
A group of people consists of men, women, and children. 40% of them are men, 35% are women, and the rest are children, and their average weights are 70 kg, 60 kg, and 30 kg, respectively. The average weight of the group is:
If the mean of 22, 25, 27, 24, and x is 26, then the value of x is:
The average of 70 values is 40. If each value is multiplied by 20, what will be the changed average?
| Marks obtained | No. of students |
| 25 | 5 |
| 30 | 6 |
| 35 | 3 |
| 40 | 1 |
The average runs scored by a batsman in 23 matches is 40. In the next 10 matches, the batsman scored an average of 16 runs. Find his average runs scored (rounded off to two decimals) in all the 33 matches.