The marks were incorrectly entered as 34 instead of the correct value of 70.
The total difference in marks is:
\( \text{Difference} = \text{Correct Marks} - \text{Incorrect Marks} \)
\( \text{Difference} = 70 - 34 = 36 \)
Let \(N\) be the total number of students in the class.
The total difference in marks (36) is distributed across all \(N\) students, causing the average to decrease.
The decrease in the average marks is given as \(\frac{4}{3}\).
Therefore, the relationship is:
\( \frac{\text{Total Difference}}{\text{Number of Students}} = \text{Average Decrease} \)
\( \frac{36}{N} = \frac{4}{3} \)
To find \(N\), we can rearrange the equation:
\( 4 \times N = 36 \times 3 \)
\( 4N = 108 \)
\( N = \frac{108}{4} \)
\( N = 27 \)
Thus, there are 27 students in the class.
| Marks obtained | No. of students |
| 25 | 5 |
| 30 | 6 |
| 35 | 3 |
| 40 | 1 |
| Age Band | Students |
|---|---|
| 0 - 10 | 4 |
| 10 - 20 | 5 |
| 20 - 30 | 15 |
| 30 - 40 | 4 |
The median of the observations 4, 14, 11, 8, 7, 8, 9, 12, 4, and 6 is:
The weights (in kg) of 9 members of a school cricket team are 50, 63, x, 62, 64, 48, 51, 55, 48. If the mean weight is 56 kg, then the value of x is:
A group of people consists of men, women, and children. 40% of them are men, 35% are women, and the rest are children, and their average weights are 70 kg, 60 kg, and 30 kg, respectively. The average weight of the group is:
If the mean of 22, 25, 27, 24, and x is 26, then the value of x is:
The average of 70 values is 40. If each value is multiplied by 20, what will be the changed average?
| Marks obtained | No. of students |
| 25 | 5 |
| 30 | 6 |
| 35 | 3 |
| 40 | 1 |
The average runs scored by a batsman in 23 matches is 40. In the next 10 matches, the batsman scored an average of 16 runs. Find his average runs scored (rounded off to two decimals) in all the 33 matches.