Calculating Force on a Conductor
The force ($F$) acting on a straight conductor carrying current ($I$) in a magnetic field ($B$) is given by the formula:
$F = BIL\sin\theta$
Where:
- $B$ is the magnetic field strength.
- $I$ is the current flowing through the conductor.
- $L$ is the length of the conductor.
- $\theta$ is the angle between the direction of the current and the magnetic field.
Applying the Formula
From the question, we have:
- Magnetic field strength, $B = 0.2$ T
- Current, $I = 5$ A
- Length of conductor, $L = 1$ m
- The conductor is placed perpendicular to the magnetic field, so $\theta = 90^\circ$.
We know that $\sin(90^\circ) = 1$. Substituting the values into the formula:
$F = (0.2 \text{ T}) \times (5 \text{ A}) \times (1 \text{ m}) \times \sin(90^\circ)$
$F = 0.2 \times 5 \times 1 \times 1$
$F = 1.0$ N
Therefore, the force acting on the conductor is 1.0 N.
Important Questions from Magnetic Force on a Current-Carrying Wire
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