A sound pulse is sent towards a cliff and an echo is heard after 1.5 s (round trip time). If the speed of sound in air is 340 m/s, the distance of the cliff from the source is :
255 m
The total distance travelled by the sound pulse is \(d_{total} = v \times t = 340 \times 1.5 = 510\ m\), since this covers the trip to the cliff and back.
Since the pulse travels to the cliff and back over this total distance, the one-way distance to the cliff is half of this: \(d = \frac{510}{2} = 255\ m\).
Therefore, the distance of the cliff from the source is 255 m.
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