A shopkeeper buys a laptop for 40,000. He first sells it at a 20% profit. Later, the buyer ₹ sells it to another person at a 10% loss. What is the final selling price of the laptop?
Option A
This is a chain-of-transactions profit-and-loss problem, where the item is sold, and then the new owner sells it again. The trick is to compute each stage on the cost price of that particular seller, because a profit or loss percentage always refers to the price at which that person bought the item.
Stage 1 — the shopkeeper sells: The shopkeeper's cost price is ₹40,000 and he books a 20% profit.
Profit = 20% of 40,000 = 0.20 × 40,000 = ₹8,000.
Selling price = 40,000 + 8,000 = ₹48,000. (Equivalently, 40,000 × 1.20 = 48,000.)
Stage 2 — the buyer resells at a 10% loss: For this second seller, the cost price is now ₹48,000 (what he paid), not the original ₹40,000. A 10% loss on 48,000:
Loss = 10% of 48,000 = 0.10 × 48,000 = ₹4,800.
Final selling price = 48,000 − 4,800 = ₹43,200. (Equivalently, 48,000 × 0.90 = 43,200.)
So the final selling price of the laptop is ₹43,200.
The most common error is to apply the 10% loss on the original ₹40,000 (giving 40,000 × 0.90 = 36,000) instead of on ₹48,000. Another mistake is to combine +20% and −10% into a net +10% and take 44,000; the successive-percentage effect is 1.20 × 0.90 = 1.08, i.e. only an 8% net gain, giving ₹43,200.
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