A series is given with one term missing. Select the correct alternative from the given ones that will complete the series.
21
The given series is: 1, 4, 3, 16, 6, 36, 10, 64, 15, 100, ?
To solve this number series problem, we need to identify the pattern governing the sequence of numbers. Observing the series, we can see that it alternates between relatively small numbers and larger numbers that appear to be perfect squares.
Let's examine the terms at odd positions and the terms at even positions separately.
The terms at the odd positions (1st, 3rd, 5th, 7th, 9th) are: 1, 3, 6, 10, 15.
Let's look at the difference between consecutive terms in this sub-series:
The differences between consecutive terms form a sequence: 2, 3, 4, 5. This sequence shows an increasing difference of 1 each time. Therefore, the next difference should be 6.
The missing term is at the 11th position, which is an odd position. To find the 11th term, we add the next difference (6) to the 9th term (15).
Next term in odd positions = 9th term + 6 = $15 + 6 = 21$.
The terms at the even positions (2nd, 4th, 6th, 8th, 10th) are: 4, 16, 36, 64, 100.
Let's look at these numbers:
The terms at even positions are the squares of even numbers: 2, 4, 6, 8, 10. The base of the square increases by 2 each time.
The missing term is at the 11th position, which is an odd position, so this even position pattern does not directly give us the missing term. However, understanding this pattern confirms the alternating nature of the series.
The missing term is the 11th term in the series. Since 11 is an odd number, the missing term follows the pattern of the terms at odd positions.
Based on our analysis of the odd positions, the next term after 15 should be $15 + 6 = 21$.
Thus, the missing term in the series is 21.
Let's check the options provided:
Our calculated missing term is 21, which matches one of the options.
| Position | Term | Type | Pattern Observed |
|---|---|---|---|
| 1st | 1 | Odd | Base for odd sequence (1) |
| 2nd | 4 | Even | $2^2$ |
| 3rd | 3 | Odd | $1 + 2$ |
| 4th | 16 | Even | $4^2$ |
| 5th | 6 | Odd | $3 + 3$ |
| 6th | 36 | Even | $6^2$ |
| 7th | 10 | Odd | $6 + 4$ |
| 8th | 64 | Even | $8^2$ |
| 9th | 15 | Odd | $10 + 5$ |
| 10th | 100 | Even | $10^2$ |
| 11th | ? | Odd | $15 + 6 = 21$ |
Number series problems often appear in logical reasoning sections of competitive exams. Identifying the pattern is key. Common types of number series include:
Practice with various types of series helps in quickly recognizing the underlying pattern during exams.
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