A series is given, with one number missing. Choose the correct alternative from the given ones that will complete the series.
1.56
This question asks us to find the missing number in a given series: 1.14, 1.28, 1.42, ?, 1.70, 1.84.
To solve a number series problem, we need to identify the pattern or rule that connects consecutive numbers in the sequence. Once the pattern is found, we can apply it to determine the missing term.
Let's examine the difference between consecutive terms in the given series:
It appears that the difference between each consecutive term is constant, which is 0.14. This indicates that the series is an arithmetic progression where each term is obtained by adding 0.14 to the previous term.
The missing number is the fourth term in the series. According to the pattern, the fourth term should be the third term plus the common difference.
Missing Term = Third Term + Common Difference
Missing Term = \(\text{1.42} + \text{0.14}\)
Let's perform the addition:
\(\begin{array}{@{}c@{\,}c@{}c@{}c} & 1 & . & 4 & 2 \\ + & 0 & . & 1 & 4 \\ \hline & 1 & . & 5 & 6 \\ \end{array}\)
So, the missing number is 1.56.
Let's check if the next term in the series follows the pattern using the calculated missing number (1.56).
This matches the given fifth term in the series (1.70). Therefore, the pattern is consistent, and the calculated missing number is correct.
The series follows a pattern where each term is obtained by adding 0.14 to the previous term. By applying this pattern, the missing number is found to be 1.56.
The completed series is: 1.14, 1.28, 1.42, 1.56, 1.70, 1.84.
| Term | Value | Difference from previous term |
|---|---|---|
| 1st | 1.14 | - |
| 2nd | 1.28 | 1.28 - 1.14 = 0.14 |
| 3rd | 1.42 | 1.42 - 1.28 = 0.14 |
| 4th (Missing) | 1.56 | 1.56 - 1.42 = 0.14 |
| 5th | 1.70 | 1.70 - 1.56 = 0.14 |
| 6th | 1.84 | 1.84 - 1.70 = 0.14 |
When tackling number series questions, remember these steps:
An arithmetic series is a sequence of numbers such that the difference between consecutive terms is constant. This constant difference is called the common difference, denoted by 'd'.
The general form of an arithmetic series is:
\(a, a+d, a+2d, a+3d, \dots\)
where 'a' is the first term and 'd' is the common difference.
In the given problem, the first term \(a = 1.14\) and the common difference \(d = 0.14\).
The nth term of an arithmetic series can be found using the formula:
\(a_n = a + (n-1)d\)
For example, the 4th term (missing term) is \(a_4 = 1.14 + (4-1) \times 0.14 = 1.14 + 3 \times 0.14 = 1.14 + 0.42 = 1.56\).
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