A railway wagon (open at the top) of mass M1 is moving with speed v1 along a straight track. As a result of rain, after some time it gets partially filled with water so that the mass of the wagon becomes M2 and speed becomes v2. Taking the rain to be falling vertically and the water stationery inside the wagon, the relation between the two speeds v1 and v2 is :
This problem involves analyzing the motion of a railway wagon as its mass changes due to falling rain. The key physical principle at play here is the conservation of momentum. Let's break down the scenario.
We have a railway wagon moving along a straight track. Rain is falling vertically into the wagon. The rain adds mass to the wagon, increasing its total mass and potentially changing its speed.
The rain is falling vertically. This means the force exerted by the rain on the wagon as it lands is primarily vertical. While there might be a vertical impulse changing the vertical momentum (causing the wagon to settle slightly on its springs, if any), there is no external force acting on the wagon-water system in the horizontal direction.
Since there is no external horizontal force, the total horizontal momentum of the system (wagon + collected rain) must be conserved.
Momentum (\({p}\)) is defined as the product of mass (\({m}\)) and velocity (\({v}\)), i.e., \({p = mv}\). Since we are considering only the horizontal motion, we will look at the horizontal components of momentum.
According to the principle of conservation of linear momentum in the absence of external horizontal forces:
Initial horizontal momentum = Final horizontal momentum
\({p_{1x} = p_{2x}}\)
\({M_1 v_1 = M_2 v_2}\)
Let's look at the provided options and compare them with our derived relation:
Therefore, the correct relation between the initial and final speeds and masses is \({M_1v_1 = M_2v_2}\).
Based on the principle of conservation of horizontal momentum, as there is no external horizontal force acting on the wagon-water system, the total horizontal momentum remains constant. The initial horizontal momentum is \({M_1v_1}\) and the final horizontal momentum is \({M_2v_2}\). Equating these gives the relation \({M_1v_1 = M_2v_2}\).
| Concept | Initial State | Final State | Relation |
|---|---|---|---|
| Mass | \({M_1}\) | \({M_2}\) (\({M_2 > M_1}\)) | Mass increases |
| Speed | \({v_1}\) | \({v_2}\) | Speed changes |
| Horizontal Momentum | \({M_1 v_1}\) | \({M_2 v_2}\) | Conserved (\({M_1 v_1 = M_2 v_2}\)) |
| External Horizontal Force | None | None | Zero |
Conservation of linear momentum is a fundamental principle in physics. It states that if no external forces act on a system, the total linear momentum of the system remains constant.
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