Hardy-Weinberg Equilibrium Principle

The Hardy-Weinberg principle states that allele and genotype frequencies in a population remain constant from generation to generation in the absence of other evolutionary influences.

Allele Frequencies Notation

In a population of diploid organisms with two alleles, A and a:

• Let the frequency of allele A be $p$.
• Let the frequency of allele a be $q$.
• It follows that $p + q = 1$.

Genotype Frequencies Calculation

Under Hardy-Weinberg equilibrium, the expected genotype frequencies are:

• Frequency of genotype AA = $p^2$
• Frequency of genotype Aa = $2pq$
• Frequency of genotype aa = $q^2$

The sum of these frequencies is $p^2 + 2pq + q^2 = 1$.

Applying Given Data

The question provides the frequency of allele A:

$p = 0.1$

Determining Frequency of AA Genotype

To find the frequency of the AA genotype, we use the formula $p^2$.

Calculation:

Frequency of AA = $p^2 = (0.1)^2$

Frequency of AA = $0.01$

Final Answer Determination

The calculation based on Hardy-Weinberg equilibrium shows the frequency of the AA genotype to be 0.01. The question indicates that Option A is the correct answer.