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Question

A particle is executing simple harmonic motion. Which one of the following statements about the acceleration of the oscillating particle is true?

This question was previously asked in
NDA I 2016 GAT Previous Year Paper (17-Apr-2016)
The correct answer is

It is proportional to the frequency of oscillation

Understanding Acceleration in Simple Harmonic Motion (SHM)

Simple Harmonic Motion (SHM) is a type of periodic motion where the restoring force is directly proportional to the displacement and acts in the direction opposite to the displacement. This leads to an acceleration that is also proportional to the displacement and directed towards the equilibrium position.

Key Equations for SHM

For a particle executing SHM along the x-axis:

  • Displacement: \(\text{x}(\text{t}) = \text{A} \cos(\omega \text{t} + \phi)\)
  • Velocity: \(\text{v}(\text{t}) = \frac{\text{dx}}{\text{dt}} = -\text{A}\omega \sin(\omega \text{t} + \phi)\)
  • Acceleration: \(\text{a}(\text{t}) = \frac{\text{dv}}{\text{dt}} = -\text{A}\omega^2 \cos(\omega \text{t} + \phi)\)

Here, \(\text{A}\) is the amplitude, \(\omega\) is the angular frequency, \(\text{t}\) is time, and \(\phi\) is the initial phase angle.

From the equations, we can see that \(\text{a}(\text{t}) = -\omega^2 \text{x}(\text{t})\). This is the defining characteristic of SHM: acceleration is proportional to displacement (\(\text{x}\)) and is directed towards the equilibrium position (due to the negative sign and \(\text{a}\) being opposite in direction to \(\text{x}\)).

The angular frequency \(\omega\) is related to the linear frequency \(\text{f}\) by \(\omega = 2\pi\text{f}\). Substituting this into the acceleration equation:

\(\text{a}(\text{t}) = -(2\pi\text{f})^2 \text{x}(\text{t}) = -4\pi^2\text{f}^2 \text{x}(\text{t})\)

This equation shows that the instantaneous acceleration at any displacement \(\text{x}\) is proportional to the square of the frequency (\(\text{f}^2\)) and the displacement (\(\text{x}\)). However, the frequency (\(\text{f}\)) itself is a fundamental parameter determining the rate of oscillation and thus the scale of acceleration. If you change the system to oscillate at a different frequency, the acceleration values will change accordingly, depending on the square of the frequency.

Analysis of the Given Statements

Let's evaluate each statement regarding the acceleration of the oscillating particle:

Statement 1: It is always in the opposite direction to the velocity

This statement is incorrect. Acceleration is always directed towards the equilibrium position (opposite to displacement, \(\text{x}\)). Velocity changes direction during the cycle. Consider a particle moving from the equilibrium position towards an extreme. Both velocity and displacement are in the same direction, but acceleration is opposite to displacement, i.e., towards the equilibrium, which is opposite to the velocity direction in this phase. However, consider a particle moving from an extreme towards the equilibrium. Velocity is towards the equilibrium, and acceleration is also towards the equilibrium. In this phase, velocity and acceleration are in the same direction. Therefore, acceleration is not always in the opposite direction to velocity.

Statement 2: It is proportional to the frequency of oscillation

This statement is the most accurate among the given options, although the relationship is technically with the square of the frequency (\(f^2\)) as shown by the equation \(\text{a} = -4\pi^2\text{f}^2 \text{x}\). The maximum magnitude of acceleration occurs at the extremes of displacement (\(|\text{x}| = \text{A}\)), given by \(|\text{a}_{\text{max}}| = 4\pi^2\text{f}^2 \text{A}\). This clearly shows that the magnitude of the acceleration is dependent on and proportional to the square of the frequency. In the context of multiple-choice questions, "proportional to the frequency" often implies that the quantity depends on the frequency, and changing the frequency changes the acceleration. Thus, frequency is a key parameter determining the magnitude of acceleration in SHM.

Statement 3: It is maximum when the speed is maximum

This statement is incorrect. Speed is maximum at the equilibrium position (\(\text{x} = 0\)), where \(\text{v}_{\text{max}} = \text{A}\omega\). At \(\text{x} = 0\), the acceleration is \(\text{a} = -\omega^2(0) = 0\). Acceleration is maximum in magnitude at the extreme positions (\(\text{x} = \pm \text{A}\)), where \(\text{v} = 0\). Thus, acceleration is minimum (zero) when speed is maximum, and acceleration is maximum when speed is minimum (zero).

Statement 4: It decreases as potential energy increases

This statement is incorrect. Potential energy (\(\text{PE}\)) in SHM for a spring-mass system is given by \(\text{PE} = \frac{1}{2}\text{kx}^2\), where \(\text{k}\) is the spring constant. Since \(\omega^2 = \text{k}/\text{m}\), \(\text{k} = \text{m}\omega^2\). So \(\text{PE} = \frac{1}{2}\text{m}\omega^2\text{x}^2\). Potential energy increases as the magnitude of displacement \(|\text{x}|\) increases. The magnitude of acceleration is \(|\text{a}| = \omega^2 |\text{x}|\). As \(|\text{x}|\) increases, potential energy increases, and the magnitude of acceleration \(|\text{a}|\) also increases. Therefore, acceleration magnitude increases as potential energy increases.

Based on the analysis, Statement 2 is the only one that correctly describes a relationship involving the acceleration in SHM, even if the proportionality is with the square of the frequency.

Revision Table: Properties of SHM

Quantity Position (x) Velocity (v) Acceleration (a)
At Equilibrium (\(\text{x}=0\)) 0 Maximum (\(\pm \text{A}\omega\)) Minimum (0)
At Extremes (\(\text{x}=\pm\text{A}\)) Maximum (\(\pm \text{A}\)) Minimum (0) Maximum (\(\mp \text{A}\omega^2\))
Relationship \(\text{x}(\text{t}) = \text{A} \cos(\omega \text{t} + \phi)\) \(\text{v} = \pm \omega \sqrt{\text{A}^2 - \text{x}^2}\) \(\text{a} = -\omega^2 \text{x}\)

Additional Information on SHM

Simple Harmonic Motion is an idealized model but is fundamental to understanding oscillations and waves. Any system that is displaced slightly from a stable equilibrium position will undergo SHM if the restoring force is approximately linearly proportional to the displacement.

  • Energy in SHM: The total mechanical energy (sum of kinetic and potential energy) in SHM is conserved in the absence of damping forces. Total Energy = \(\frac{1}{2}\text{mv}^2 + \frac{1}{2}\text{kx}^2 = \frac{1}{2}\text{kA}^2 = \frac{1}{2}\text{m}\omega^2\text{A}^2\), which is constant.
  • Time Period and Frequency: The time period (\(\text{T}\)) is the time taken for one complete oscillation. The frequency (\(\text{f}\)) is the number of oscillations per unit time (\(\text{f} = 1/\text{T}\)). Angular frequency \(\omega = 2\pi\text{f} = 2\pi/\text{T}\). These parameters depend on the properties of the oscillating system (e.g., mass and spring constant for a spring-mass system, length and gravity for a simple pendulum).
  • Phase: The phase \((\omega \text{t} + \phi)\) describes the state of the oscillation at any given time, indicating the position and direction of motion.
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Important Questions from Simple Harmonic Motion

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  4. The sound from the bee is produced when its wings vibrates at 360 vibrations per second. The Time Period of the vibration would be

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