The sound from the bee is produced when its wings vibrates at 360 vibrations per second. The Time Period of the vibration would be
1 / 360
Understanding Bee Wing Vibration and Time Period
The question asks about the time period of the vibration of a bee's wings, given the frequency of vibration. Sound is produced by vibrations. In this case, the buzzing sound from a bee comes from its wings vibrating very rapidly.
We are given that the wings vibrate at a frequency of 360 vibrations per second. The frequency of vibration is a measure of how many times the vibration occurs in one second. It is usually denoted by 'f' and its unit is Hertz (Hz), where 1 Hz is equal to 1 vibration per second.
So, the given frequency is:
\(f = 360\) vibrations per second or \(f = 360 \, \text{Hz}\).
The time period (T) of a vibration is the time taken for one complete vibration. The time period and frequency are related by a simple formula:
The time period is the reciprocal of the frequency.
\(T = \frac{1}{f}\)
Let's use this formula to calculate the time period of the bee's wing vibration.
We are given \(f = 360 \, \text{Hz}\).
Substituting this value into the formula for the time period:
\(T = \frac{1}{360}\)
The unit of time period is seconds (s).
Therefore, the time period of the bee's wing vibration is \(1/360\) seconds.
Key Concepts: Frequency and Time Period
- Frequency: The number of complete cycles or vibrations in one second. Unit is Hertz (Hz).
- Time Period: The time taken for one complete cycle or vibration. Unit is seconds (s).
- Relationship: Time Period = 1 / Frequency (\(T = 1/f\)).
Let's verify the calculation with the given options.
The calculated time period is \(1/360\) seconds.
Comparing this with the options:
- Option 1: \(1/6\)
- Option 2: \(1/36\)
- Option 3: \(1/360\)
- Option 4: \(1/216\)
Our calculated time period matches Option 3.
In summary, the sound is produced due to the vibration of the bee's wings. The frequency tells us how fast the wings vibrate, and the time period tells us how long one single up-and-down movement of the wing takes. Since the frequency is 360 vibrations per second, each vibration takes \(1/360\) of a second.
Important Questions from Simple Harmonic Motion
A particle is executing SHM of amplitude 9 and time period of 4 seconds, then the time taken by it to move from the extreme position to half the amplitude is
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