A number is as much greater than 50 as it is lesser than 84. What is the number?
67
The problem asks us to find a number that is the same distance away from 50 as it is from 84. Let's call the unknown number \(x\).
According to the question:
The phrase "as much greater than 50 as it is lesser than 84" tells us that these two differences are equal. So, we can set up an equation:
\[x - 50 = 84 - x\]
Now, we need to solve this equation for \(x\). To do this, we can gather the \(x\) terms on one side and the constant terms on the other side.
Add \(x\) to both sides of the equation:
\[x - 50 + x = 84 - x + x\] \[2x - 50 = 84\]
Add 50 to both sides of the equation:
\[2x - 50 + 50 = 84 + 50\] \[2x = 134\]
Finally, divide both sides by 2 to find the value of \(x\):
\[\frac{2x}{2} = \frac{134}{2}\] \[x = 67\]
So, the number is 67.
We can check this by verifying if 67 is the same distance from 50 and 84:
Since \(17 = 17\), our answer is correct. The number is indeed 67.
| Concept | Description | Application in Problem |
|---|---|---|
| Algebraic Equation | A mathematical statement that two expressions are equal, often containing variables. | Setting up \(x - 50 = 84 - x\) to represent the problem. |
| Solving Linear Equations | Finding the value(s) of the variable(s) that make the equation true. | Using addition and division to isolate \(x\) and find its value. |
| Representing Differences | Using subtraction to show how much greater or lesser one number is compared to another. | \(x - 50\) for "greater than 50" and \(84 - x\) for "lesser than 84". |
Another way to think about a number that is "as much greater than A as it is lesser than B" is that the number is exactly in the middle of A and B. In other words, the number is the average (or midpoint) of A and B.
The formula for the average of two numbers, A and B, is:
\[\text{Average} = \frac{A + B}{2}\]
In this problem, A = 50 and B = 84. Let's use the average formula to find the number:
\[\text{Number} = \frac{50 + 84}{2}\] \[\text{Number} = \frac{134}{2}\] \[\text{Number} = 67\]
This method gives the same result and provides a quicker way to solve this specific type of problem.
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