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Question

A mixer stage has a noise figure of 20 dB and is preceded by an amplifier that has a noise figure of 9 dB and an available power gain of 15 dB. The overall noise figure is :

This question was previously asked in
UGC NET 2015 Paper 3 Electronic Science Question Paper (28-Jun-2015)
The correct answer is

10.44 dB

Friis's formula must be used with ratios, never with decibels — that is the whole discipline of this calculation.

\(F_{total}=F_{1}+\dfrac{F_{2}-1}{G_{1}}\)

Step 1 — convert everything out of dB.

QuantitydBRatio
F1 (amplifier)9\(10^{0.9}=7.943\)
G1 (amplifier)15\(10^{1.5}=31.62\)
F2 (mixer)20\(10^{2}=100\)

Step 2 — apply Friis.

\(F_{total}=7.943+\dfrac{100-1}{31.62}=7.943+3.131=11.074\)

Step 3 — convert back to decibels.

\(F_{dB}=10\log_{10}(11.074)=10\times1.0443=10.44\ \text{dB}\)

which is option 3.

Notice what the arithmetic reveals. The mixer is a dreadful stage — 20 dB noise figure, a hundredfold degradation on its own — yet the system ends at only 10.44 dB, barely 1.4 dB worse than the amplifier alone. The 31.6-fold gain ahead of it divides the mixer's contribution down to 3.13, a small addition to the amplifier's 7.94. This is precisely why every sensitive receiver puts a low-noise amplifier first and tolerates a noisy mixer afterwards.

Option 4, 11.07 dB, is the deliberate trap — it is the correct ratio 11.074 mislabelled as decibels. Option 2, 11.44 dB, is what a careless dB-domain addition would give. Both are reminders that the only legitimate arithmetic is in ratios.

The general cascaded form extends the same idea down the chain:

\(F_{total}=F_{1}+\dfrac{F_{2}-1}{G_{1}}+\dfrac{F_{3}-1}{G_{1}G_{2}}+\cdots\)

Each stage's contribution is divided by the product of all the gains preceding it, so the influence of later stages decays geometrically. The corollary is unforgiving: anything lossy placed first — a long cable, a filter, a switch — has gain less than one and therefore multiplies the following stages' contributions, which is why the LNA is mounted at the antenna feed rather than at the receiver end of the cable.

Hence, the overall noise figure is 10.44 dB.

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Similar Questions

  1. Which of the following are useful in comparing the noise performance of receivers ?

    1. Input noise voltage
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Important Questions from Noise Temperature and Noise Figure

  1. Which of the following is not a primary source of external noise?

  2. If each stage had a gain of 10 dB, and Noise Figure of 10 dB, then the overall Noise figure of a two-stage cascade amplifier will be

  3. An antenna pointing in a certain direction has a noise temperature of 50 K. The ambient temperature is 290 K. The antenna is connected to a pre-amplifier that has a noise figure of 2 dB and an available gain of 40 dB over an effective bandwidth of 12 MHz. The effective input noise temperature Te for the amplifier and the noise power Pao at the output of the preamplifier, respectively, are

  4. The noise figure of an amplifier is 3 dB. Its noise temperature will be about

  5. Which of the following are useful in comparing the noise performance of receivers ?

    1. Input noise voltage
    2. Equivalent noise resistance
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