A man buy two watches at Rs.4000. He sold one watch at 20% profit and second at 10% loss. In this transaction the overall profit or loss will be 5%.Find the cost price of first watch.
Rs.2000
The problem asks us to find the cost price (CP) of the first watch purchased by a man. We know the total cost of two watches, the profit percentage on the first watch, the loss percentage on the second watch, and the overall profit percentage on the entire transaction.
Here's a summary of the provided information:
| Total Cost Price (CP) of two watches | Rs. 4000 |
| Watch 1: Profit Percentage | 20% |
| Watch 2: Loss Percentage | 10% |
| Overall Transaction Profit Percentage | 5% |
We'll use algebraic equations to solve this. Let:
Based on the details, we can write:
So, the second key equation is:
1.20 $\times$ CP1 + 0.90 $\times$ CP2 = 4200 --(Equation 2)
We need to solve the system of two equations:
From Equation 1, express CP2:
CP2 = 4000 - CP1
Substitute this into Equation 2:
1.20 $\times$ CP1 + 0.90 $\times$ (4000 - CP1) = 4200
Distribute the 0.90:
1.20 $\times$ CP1 + 3600 - 0.90 $\times$ CP1 = 4200
Group the CP1 terms:
(1.20 - 0.90) $\times$ CP1 = 4200 - 3600
0.30 $\times$ CP1 = 600
Calculate CP1:
CP1 = $\frac{600}{0.30}
CP1 = 2000
The calculation shows that the cost price of the first watch is Rs. 2000.
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