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Question

A light bulb rated as 60 W at 220 V has a potential difference of 110 V across its ends. The power dissipated in this light bulb is:

This question was previously asked in
CDS 2 2025 Maths Question Paper (14-Sep-2025)
The correct answer is

15 W

Explanation: \(P = \left(\frac{V}{V_{\text{rated}}}\right)^2 \times P_{\text{rated}} = \left(\frac{110}{220}\right)^2 \times 60 = \left(\frac{1}{2}\right)^2 \times 60 = 15 \, \text{W}\)

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