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Question

A glass jar contains 6 white, 8 black, 4 red and 3 blue marbles. If a single marble is chosen at random from the jar, what is the probability that it is black or blue?

This question was previously asked in
SSC CGL 2022 Tier-II (Paper 2 JSO) Previous Year Paper (04-Mar-2023)
The correct answer is \(\frac{11}{21}\)

Understanding Marble Probability

This problem asks us to find the probability of drawing a black or a blue marble from a glass jar containing marbles of different colors. Probability is calculated as the ratio of the number of favorable outcomes to the total number of possible outcomes.

Calculating Total Possible Outcomes

First, let's find the total number of marbles in the jar. The jar contains:

  • 6 white marbles
  • 8 black marbles
  • 4 red marbles
  • 3 blue marbles

The total number of marbles is the sum of the marbles of all colors:

Total marbles = Number of white + Number of black + Number of red + Number of blue

Total marbles = \(6 + 8 + 4 + 3 = 21\)

So, there are 21 possible outcomes when selecting a single marble from the jar.

Marble Color Quantity
White 6
Black 8
Red 4
Blue 3
Total 21

Identifying Favorable Outcomes (Black or Blue)

We are interested in the probability of drawing a marble that is either black or blue. These are our favorable outcomes. The number of favorable outcomes is the total number of black marbles plus the total number of blue marbles, because a marble cannot be both black and blue at the same time (these events are mutually exclusive).

Number of black marbles = 8

Number of blue marbles = 3

Number of favorable outcomes (black or blue) = Number of black marbles + Number of blue marbles

Number of favorable outcomes = \(8 + 3 = 11\)

Calculating the Probability

The probability of an event is given by the formula:

P(Event) = \(\frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}\)

In this case, the event is drawing a black or blue marble.

P(Black or Blue) = \(\frac{\text{Number of black or blue marbles}}{\text{Total number of marbles}}\)

P(Black or Blue) = \(\frac{11}{21}\)

Therefore, the probability of choosing a black or blue marble is \(\frac{11}{21}\).

Summary of Probability Calculation

  • Total marbles in the jar = 21
  • Number of black marbles = 8
  • Number of blue marbles = 3
  • Number of black or blue marbles = \(8 + 3 = 11\)
  • Probability (Black or Blue) = \(\frac{11}{21}\)

Revision Table: Key Probability Concepts

Concept Explanation Formula Example
Probability Likelihood of an event occurring. P(Event) = \(\frac{\text{Favorable Outcomes}}{\text{Total Outcomes}}\)
Mutually Exclusive Events Events that cannot happen at the same time (e.g., drawing a black marble and a red marble in a single draw). P(A or B) = P(A) + P(B) for mutually exclusive events A and B.
Total Outcomes The total number of possible results of an experiment. Sum of all possible individual outcomes.
Favorable Outcomes The outcomes that satisfy the condition of the event we are interested in. The specific outcomes counted for the desired event.

Additional Information: Probability Rules

When dealing with probabilities, especially involving multiple events, it's important to understand key rules:

  • Addition Rule for Mutually Exclusive Events: As used in this problem, if two events A and B are mutually exclusive (cannot occur together), the probability that either A or B occurs is the sum of their individual probabilities: \(P(A \text{ or } B) = P(A) + P(B)\).
    • In our case, drawing a black marble (Event A) and drawing a blue marble (Event B) are mutually exclusive.
    • \(P(\text{Black}) = \frac{8}{21}\)
    • \(P(\text{Blue}) = \frac{3}{21}\)
    • \(P(\text{Black or Blue}) = P(\text{Black}) + P(\text{Blue}) = \frac{8}{21} + \frac{3}{21} = \frac{8+3}{21} = \frac{11}{21}\). This confirms our calculation.
  • Addition Rule for Non-Mutually Exclusive Events: If two events A and B are not mutually exclusive (can occur together), the probability that either A or B occurs is the sum of their individual probabilities minus the probability of both occurring: \(P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B)\). This rule was not needed here because drawing a black and a blue marble simultaneously in a single draw is impossible.
  • Multiplication Rule for Independent Events: If two events A and B are independent (the outcome of one doesn't affect the other), the probability that both A and B occur is the product of their individual probabilities: \(P(A \text{ and } B) = P(A) \times P(B)\). This is typically used for sequential events with replacement or events from different sources.

Understanding these rules helps in solving various probability problems, whether dealing with marbles, cards, dice, or other random events.

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Important Questions from Probability

  1. Two dice are thrown simultaneously. What is the probability of getting the same number on both the dice?

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