A girl with 50 kg mass climbs up a rope through a height of 5 metres. She takes 25 s to accomplish the task. What is the power (in watts) expended by the girl?
98
Power measures how fast work is done and is defined as work divided by time, \(P=\dfrac{W}{t}\).
When the girl climbs the rope, she does work against gravity by raising her body weight through a height, so the work done is \(W=mgh\).
The given data are mass \(m=50\ \text{kg}\), height \(h=5\ \text{m}\), time \(t=25\ \text{s}\), with \(g=9.8\ \text{m/s}^2\).
Work done: \(W=50\times 9.8\times 5=2450\ \text{J}\).
Power: \(P=\dfrac{2450}{25}=98\ \text{W}\).
The key concept is that gravitational potential energy gained per unit time equals the power expended.
Hence, the power expended by the girl is 98 watts.
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