A five-digit number 7549A is divisible by 4 and 3. If it is divided by 12, what will be the remainder?
0
Divisible by 4 requires the last two digits '9A' to be divisible by 4, giving A=2 (92) or A=6 (96).
Divisible by 3 requires the digit sum \(7+5+4+9+A=25+A\) to be divisible by 3: A=2 gives sum 27 (divisible), A=6 gives sum 31 (not divisible).
So A=2, making the number 75492, which is divisible by both 4 and 3, hence by 12.
Since 75492 is exactly divisible by 12, the remainder is 0.
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If the 8-digit number 888x53y4 is divisible by 72, then what is the value of (7x + 2y), for the maximum value of y?
If all positive divisors of 132 are arranged in descending order, then what digit will be at unit place of first divisor ?
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The number 3798125P369 is divisible by 7. What is the value of the digit P?
Consider all 3-digit numbers (without repetition of digits) obtained using three non-zero digits which are multiples of 3. Let S be their sum.
Which of the following is/are correct?
1. S is always divisible by 74.
2. S is always divisible by 9.
select the correct answer using the code given below:
