A five-digit number 7549A is divisible by 4 and 3. If it is divided by 12, what will be the remainder?
0
Divisible by 4 requires the last two digits '9A' to be divisible by 4, giving A=2 (92) or A=6 (96).
Divisible by 3 requires the digit sum \(7+5+4+9+A=25+A\) to be divisible by 3: A=2 gives sum 27 (divisible), A=6 gives sum 31 (not divisible).
So A=2, making the number 75492, which is divisible by both 4 and 3, hence by 12.
Since 75492 is exactly divisible by 12, the remainder is 0.
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