A dealer sells a product at 15% profit. If he had bought it at 10% less and sold it for ₹126 less, he would have gained 20%. Find the cost price.
₹1,800
Let the original cost price be \(x\).
Original selling price at 15% profit: \(SP_1 = 1.15x\).
In the second case, the cost price is 10% less: \(0.9x\), and the gain is 20%, so the second selling price is \(SP_2 = 1.2 \times 0.9x = 1.08x\).
The second selling price is ₹126 less than the first: \(1.15x - 126 = 1.08x\).
Rearranging: \(1.15x - 1.08x = 126\), so \(0.07x = 126\).
Therefore \(x = \frac{126}{0.07} = 1800\).
Hence, the cost price is ₹1,800.
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