A, D, F, G, H and S live on six different floors of the same building. The lowermost floor in the building is numbered 1, the floor above it, number 2 and so on till the topmost floor is numbered 6. F lives on an even numbered floor but not 4. The sum of floors on which F and H live is 9. Only 3 people live between G and D. The sum of floors on which S and D live is 3. What is the sum of floors on which A and G live?
9
F lives on an even floor but not 4, and F + H = 9. Testing F = 6 gives H = 3 (both valid); F = 2 would need H = 7, which fits, but combined with the other clues only F = 6, H = 3 is consistent.
Only 3 people live between G and D, so their floors differ by 4; among the remaining floors {1, 2, 4, 5}, only the pair {1, 5} differs by 4.
The sum of the floors of S and D is 3. If D = 1, then S = 2 (valid); this forces G = 5, leaving floor 4 for A.
Sum of floors of A and G = 4 + 5 = 9.
Hence, this is the correct answer.
Similar Questions
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Important Questions from Floor Puzzle
- If P is on the first step, on which step is S?
- If P is on the first step, which of the following is true?
- If T was on the third step, which of the following pairs is incorrect?
If T joined P, Q, R and S, and T was on the third step, and Q was on a higher step than T, which step must be vacant?
If there are two steps in between the steps on which A and D are standing and C is standing on Step 6, A must be standing on which of the following steps?
