A, D, F, G, H and S live on six different floors of the same building. The lowermost floor in the building is numbered 1, the floor above it, number 2 and so on till the topmost floor is numbered 6. S lives on an even numbered floor but not 6. The sum of floors on which A and S live is 9. The sum of floors on which S and H live is 5. D lives immediately below F. What is the sum of floors on which D and F live?
5
Since S lives on an even floor but not floor 6, S must live on floor 2 or floor 4.
If S = 2, then the sum of floors for A and S being 9 would require A to live on floor 7, which does not exist, so S must be floor 4. This gives A = 9 − 4 = 5, and since the sum of S and H's floors is 5, H = 5 − 4 = 1.
The remaining floors 2, 3 and 6 are left for D, F and G. Since D lives immediately below F, the only consecutive pair available is D = 2 and F = 3, leaving G on floor 6.
The sum of floors for D and F = 2 + 3 = 5. Hence, the correct answer is 5.
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Important Questions from Floor Puzzle
- If P is on the first step, on which step is S?
- If P is on the first step, which of the following is true?
- If T was on the third step, which of the following pairs is incorrect?
If T joined P, Q, R and S, and T was on the third step, and Q was on a higher step than T, which step must be vacant?
If there are two steps in between the steps on which A and D are standing and C is standing on Step 6, A must be standing on which of the following steps?
