\(\left(\text{Take } \pi = \frac{22}{7}\right)\)
The problem asks for the outer radius of a cylindrical rod given its outer curved surface area and length.
The formula for the curved surface area (CSA) of a cylinder is:
CSA = \(2 \pi r h\)
where \(r\) is the radius and \(h\) is the height (or length) of the cylinder.
\(7500 = 2 \times \frac{22}{7} \times r \times 92\)
\(7500 = \frac{44}{7} \times 92 \times r\)
\(7500 = \frac{4048}{7} \times r\)
\(r = \frac{7500 \times 7}{4048}\)
\(r = \frac{52500}{4048}\)
\(r \approx 12.969367... \text{ cm}\)
\(r \approx 12.97 \text{ cm}\)
The outer radius of the rod is approximately 12.97 cm.
There is a wooden block in the form of a cube whose each side is 8 meters long.
The maximum possible number of cylinders with a diameter of 1 meter and a height of 4 meters were cut from this block. The cylinders are to be painted at the rate of ₹14 per square meter.
What is the total amount (in ₹) needed to paint all the cylinders if we paint the entire surface of each cylinder? (Take $\pi = \frac{22}{7}$)