A cyclist travels from point A to B and then returns from B to A along the same route. On the onward journey, he covers two-fifths of the distance at 15 km/hr and the remaining distance at 20 km/hr. On the return journey, he covers one-fourth of the distance at 16 km/hr and the remaining distance at 24 km/hr. Find the average for the entire trip. (Round off your answer to two decimal places.)
19.32 km/hr
Let the one-way distance be 300 km (a convenient common multiple).
Onward: \(\tfrac25\times300=120\) km at 15 km/h takes \(8\) h; remaining \(180\) km at 20 km/h takes \(9\) h. Onward time = 17 h.
Return: \(\tfrac14\times300=75\) km at 16 km/h takes \(4.6875\) h; remaining \(225\) km at 24 km/h takes \(9.375\) h. Return time = 14.0625 h.
Total distance: \(600\) km. Total time: \(17+14.0625 = 31.0625\) h.
Average speed: \(\dfrac{600}{31.0625} \approx 19.32\) km/hr.
Hence, the average speed for the entire trip is approximately 19.32 km/hr.
Similar Questions
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Important Questions from Average Speed
A car runs first 275 km at an average speed of 50 km/h and the next 315 km at an average speed of 70 km/h. What is the average speed ( in km/h) for the entire journey?
Akhil rides first 12 km at a speed of 16 km/h and further 6 km at a speed of 20 km/h. Find his average speed (in km/h).
Shyam drives his car 30 km at a speed of 45 km/h and, for the next 1 h 20 m, he drives it at a speed of 51 km/h. Find his average speed (in km/h) for the entire journey.
X and Y travel a distance of 90 km each such that the speed of Y is greater than that of X. The sum of their speeds is 100 km/h and the total time taken by both is 3 hours 45 minutes. The ratio of the speed of X to that of Y is:
If a man travels at \(\frac{1}{x}\) km/h on a journey and returns at \(\rm \frac{1}{x^2}\) km/h, then his average speed for the journey is:
