A clean and dry core sample weighing 425 gram was 100% saturated with a 1.07 specific gravity brine. The new weight is 453 gram. The core sample is 12 cm long and 4 cm in diameter. The percentage of porosity of the rock sample will be .................. .
17.30%
Porosity is the ratio of pore volume to bulk volume. When a dry core is fully saturated with brine, the gain in weight equals the mass of brine filling the pores, and dividing that mass by the brine density gives the pore volume.
Step 1 — Mass of brine in the pores: \(453 - 425 = 28\ \text{g}\).
Step 2 — Brine density is 1.07 g/cm3, so the pore volume is \(V_p = \dfrac{28}{1.07} \approx 26.17\ \text{cm}^3\).
Step 3 — Bulk volume of the cylinder with radius 2 cm and length 12 cm: \(V_b = \pi r^2 h = \pi \times 2^2 \times 12 \approx 150.8\ \text{cm}^3\).
Step 4 — Porosity: \(\phi = \dfrac{V_p}{V_b} \times 100 = \dfrac{26.17}{150.8} \times 100 \approx 17.3\%\).
Values of 7 %, 25 % or 27.3 % would need pore volumes of roughly 10.6, 37.7 or 41.2 cm3, which do not match the 26.17 cm3 of brine actually taken up; only about 17.3 % fits the data.
17.30% option is correct.
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