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A car of mass 800 kg is travelling at a speed of 40 km/h on a straight road. A force of 1000 N is applied on it in the direction of its velocity for 12 s. Which one among the following is the final speed of the car?

This question was previously asked in
CDS 2 2026 Maths Question Paper (13-Sep-2026)
The correct answer is

94 km/h

Acceleration a = F/m = 1000/800 = 1.25 m/s². Initial speed u = 40 km/h ≈ 11.11 m/s, so after 12 s, final speed v = u + at = 11.11 + (1.25×12) = 26.11 m/s, which equals 94 km/h. Hence the final speed of the car is 94 km/h.

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